Worked example
Find the distance from (1, 2) to (4, 6).
Answer & why
Answer: 5
The changes are 3 and 4; √(32 + 42) = 5 coordinate units.
Grade 10 · Math
Use horizontal and vertical changes to find distance between two points.
8 generated examples + worked example

Answer: 5
The changes are 3 and 4; √(32 + 42) = 5 coordinate units.
8 reproducible examples from this math generator. Choose New examples for another set.
Question 1
Use the horizontal and vertical changes as the legs of a right triangle.
Answer: 13
The horizontal change is 5 and the vertical change is 12. Distance = √(52 + 122) = √169 = 13.
Question 2
Use the horizontal and vertical changes as the legs of a right triangle.
Answer: 13
The horizontal change is 5 and the vertical change is 12. Distance = √(52 + 122) = √169 = 13.
Question 3
Use the horizontal and vertical changes as the legs of a right triangle.
Answer: 5
The horizontal change is 3 and the vertical change is 4. Distance = √(32 + 42) = √25 = 5.
Question 4
Use the horizontal and vertical changes as the legs of a right triangle.
Answer: 25
The horizontal change is 7 and the vertical change is 24. Distance = √(72 + 242) = √625 = 25.
Question 5
Use the horizontal and vertical changes as the legs of a right triangle.
Answer: 13
The horizontal change is 5 and the vertical change is 12. Distance = √(52 + 122) = √169 = 13.
Question 6
Use the horizontal and vertical changes as the legs of a right triangle.
Answer: 5
The horizontal change is 3 and the vertical change is 4. Distance = √(32 + 42) = √25 = 5.
Question 7
Use the horizontal and vertical changes as the legs of a right triangle.
Answer: 13
The horizontal change is 5 and the vertical change is 12. Distance = √(52 + 122) = √169 = 13.
Question 8
Use the horizontal and vertical changes as the legs of a right triangle.
Answer: 5
The horizontal change is 3 and the vertical change is 4. Distance = √(32 + 42) = √25 = 5.