A model filter is tested with harmless visible particles. An equal-volume sample has 100 counted particles before filtering and 20 after. What percentage reduction is shown?
Answer & why
Answer: 80%
The reduction is 100 − 20 = 80 particles. Divide by the starting count and multiply by 100: 80/100 × 100 = 80%. This tests counted particles, not all possible water contaminants.
A model filter is tested with harmless visible particles. An equal-volume sample has 60 counted particles before filtering and 30 after. What percentage reduction is shown?
The reduction is 60 − 30 = 30 particles. Divide by the starting count and multiply by 100: 30/60 × 100 = 50%. This tests counted particles, not all possible water contaminants.
A model filter is tested with harmless visible particles. An equal-volume sample has 200 counted particles before filtering and 50 after. What percentage reduction is shown?
The reduction is 200 − 50 = 150 particles. Divide by the starting count and multiply by 100: 150/200 × 100 = 75%. This tests counted particles, not all possible water contaminants.
A model filter is tested with harmless visible particles. An equal-volume sample has 120 counted particles before filtering and 30 after. What percentage reduction is shown?
The reduction is 120 − 30 = 90 particles. Divide by the starting count and multiply by 100: 90/120 × 100 = 75%. This tests counted particles, not all possible water contaminants.
A model filter is tested with harmless visible particles. An equal-volume sample has 50 counted particles before filtering and 5 after. What percentage reduction is shown?
The reduction is 50 − 5 = 45 particles. Divide by the starting count and multiply by 100: 45/50 × 100 = 90%. This tests counted particles, not all possible water contaminants.
A model filter is tested with harmless visible particles. An equal-volume sample has 100 counted particles before filtering and 20 after. What percentage reduction is shown?
The reduction is 100 − 20 = 80 particles. Divide by the starting count and multiply by 100: 80/100 × 100 = 80%. This tests counted particles, not all possible water contaminants.
A model filter is tested with harmless visible particles. An equal-volume sample has 80 counted particles before filtering and 20 after. What percentage reduction is shown?
The reduction is 80 − 20 = 60 particles. Divide by the starting count and multiply by 100: 60/80 × 100 = 75%. This tests counted particles, not all possible water contaminants.