Worked example
A motor receives 100 J and transfers 40 J to useful lifting. What is its efficiency for lifting?
Answer & why
Answer: 40%
40 ÷ 100 × 100% = 40%.
Grade 9 · Science
Use a stated system boundary to calculate efficiency and account for energy transferred to other forms.
6 authored questions + worked example

Answer: 40%
40 ÷ 100 × 100% = 40%.
All 6 authored questions for this skill.
Question 1
Efficiency = useful output ÷ total input × 100%; energy not counted as useful is still transferred somewhere.
Answer: Motor B
B provides 70% useful output; A provides 50%.
Question 2
Efficiency = useful output ÷ total input × 100%; energy not counted as useful is still transferred somewhere.
Answer: The measurements or completeness of the energy account.
The stated account supplies less energy than its claimed output.
Question 3
Efficiency = useful output ÷ total input × 100%; energy not counted as useful is still transferred somewhere.
Answer: 90%
270 ÷ 300 × 100% = 90%.
Question 4
Efficiency = useful output ÷ total input × 100%; energy not counted as useful is still transferred somewhere.
Answer: Some kinetic energy is transferred into thermal energy.
The energy changes distribution and form rather than disappearing.
Question 5
Efficiency = useful output ÷ total input × 100%; energy not counted as useful is still transferred somewhere.
Answer: 40%
40 ÷ 100 × 100% = 40%.
Question 6
Efficiency = useful output ÷ total input × 100%; energy not counted as useful is still transferred somewhere.
Answer: 60 J
80 − 20 = 60 J; it remains part of the energy account.